There is magnetic force. A moving charge across a magnetic feild experiences it and it is always perpendicular to motion of the charge. So it changes the direction of motion. Since magnets are basically objects with electrons spinning in an oriented fashion, making a current loop(like an electromagnet), it is also appling to the macroscopic case. But the work done is probably done by electric feild in some manner as the title implies. I don’t know how exactly it plays out though.
But magnetic force does no work to a charged particle in any way. While gravitational force CAN do work and it does work on most cases(every non circular orbits or just a mass falling down). That’s why magnetic force case is emphasised.
But on your take about magnets, its not the magnetic force that do the work but the associated electric force
Gravity does no work on satellites or objects that go in circular orbits. The force is there but it does no work and hence no energy change/transfer. Work is defined based on energy change by work-energy theorem
It’s usually said about a charge under a magnetic feild. The magnetic force goes perpendicular to the direction of motion of the charge(F=q*v×B). Work is done only if the force is applied along the direction of motion. So on a moving charge, magnetic force does no work.
Not sure how that plays on magnets though. Magnets are magnetic because electrons go in circles producing the feild, and it might be because electric feild comes in and do the work but it’s not clear for me either
I am thinking, that when ionised, electron pressure only holds electrons away but does not prevent nuclear collisions because they are unbounded to electrons. But when not ionised, atoms are being pused together with electron repulsion holding back the nucleus.
I also doubt if the furnace is cold and high pressure, overcoming electron degeneracy pressure causes inverse beta decay and turns the thing into a neutron star? Then you wouldn’t get new elements but a pile of neutrons?
In stars, nuclear reactions happen at high temperatures and pressure and at death stage of a massive star(becoming a neutron star), all the electron degeneracy pressure is overcame by gravity and the same inverse beta decay happens and protons and electrons combine to give massive pile of neutrons.
If you think of a bunch of solid atoms(low temp) put in high pressure, why would nucleus react anyway? Nucleus are bound by electrons and are not able to collide with other nucleus in that state. Electrons need to combine into the nucleus with high pressure. For the case of hot plasma, nucleus are able to move through the electrons and react. You don’t need to overcome electron degeneracy pressure for that.
(I think i said things that i earlier said i’m not sure about, but this is a bit more thoughtful response while others were sent in a hurry mind)
Power plant🌱
*powerhouses might be better(it sounds better for me)
Error: url1 and url2 are the same
Higher heat also means more violent collisions. It would be much harder to collide nucleus by just pressing it. But yeah maybe with even more pressure it might happen but nuclear reactions usually happen with high speed collisions.
When electrons are bound to nucleus, it may prevent collision by having an additional layer causing degeneracy pressure between two colliding nucleus. That won’t happen if electrons are unbounded to nucleus. Atleast that’s what i imagine
I guess to overcome electron degeneracy pressure. Nucleus would collide more easily when electrons are stripped away. Not sure if i am conpletely true though
Its harder but its necessary i guess. For ionisation
I am worried about 2000ms ping
What about the inverse beta decay thing? If electrons are also being compressed it should end up becoming neutrons right?
Electron repulsion might be irrelevant but being bound to electrons isn’t. Electrons aren’t being thrown out of the orbit here since its cold. It’s getting squished into.
(I also disagree with the net zero claim, due to the sheilding effect of outer electrons, but still that too is irrelevant so np)